You would be mistaken on both counts.
The issue I have with your analysis is that your "58% win" is fully dependent on scoring two touchdowns, thus the idea that it represents a true probability of winning the game is at best a conclusion that can be easily misinterpreted.
Prob(B | A) = Prob(B and A) / Prob (A) is how conditional probability is measured, but in no event can your analysis be construed as a straightforward conditional probability; only from the standpoint that you know what you achieved on the first PAT, thus you know what you need to do on the second. However, I see nothing resembling a conditional probability in your calculations, you are treating each PAT as independent events because you are merely multiplying the Prob(A) by the Prob(B), where A is the PAT after first TD and B is the PAT after the second TD.
The proper way to evaluate the optimum strategy is to compare going for 2 PAT after the first TD strategy against the other two possible strategies, namely 1) Go for 1 PAT first and then go for 2 PAT in all cases, and 2) go for the 1 PAT first and then go for whatever is necessary to achieve a tie game.
I agree, the first strategy is optimum, but it is dependent on the ability to convert the 2 PAT being 36% or better, assuming the probability of converting the 1 PAT is 95%, the chance of winning in OT is 50%, and the certainty of scoring 2 TDs. So, if you are going to employ this strategy, you need to have a good estimate of your chances to convert the 2 PAT, you cannot just assume a global average. And as I have commented previously, I would be hard pressed to place Iowa's in the Purdue game of anything above 30%, especially if I presume the 47% success rate was from the NFL after moving the 2 PAT to the 2 yard line.
Please feel free to respond, I enjoy a good discussion.